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A homozygous tall, red flower plant was crossed with a homozygous dwarf, white flower ...

A homozygous tall, red flower plant was crossed with a homozygous dwarf, white flower plant. The F1 were selfed and 160 F2 plants were obtained.

a.(i) Name the type of genetic cross. [1 marks]
(ii) State one reason for the answer in 4(a)(i). [1 marks]
b.(i) What is evolution? [2 marks]
(ii) With the aid of a genetic diagram, state the phenotypic ratio of F2 generation. [13 marks]
(iii) Calculate the number of tall and white flowers that would be obtained in the F2 generation. [3 marks]
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    Correct Answer: Option
    Explanation:

    a. (i) Type of genetic cross: Dihybrid
    (ii) Reason for answer: Two characters are involved in the cross/involves two characters separable in inheritance.
    b. (i) Phenotype of F1: Tall and Red.
    (ii) Genetic Diagram
    Let T represent the gene for Tallness;
    t represent the gene for Dwarfism;
    R represent the gene for Red;
    r represent the gene for White.

    OR
    Parental genotype TtRr X TtRr

    X TR Tr tR tr
    TR TTRRTallRed TTRrTallRed TtRRTallRed TtRrTallRed
    Tr TTRrTallRed TTrrTallWhite TtRrTallRed TtrrTallWhite
    tR TtRRTallRed TtRrTallRed ttRRDwarf Red ttRrDwarfRed
    tr TtRrTallRed TtrrTallWhite ttRRDwarfRed ttrrDwarfWhite




    Crosses of parental genotypes
    Tall and Red - 9
    Tall and White - 3
    Dwarf and Red - 3
    Dwarf and White - 1
    Parental genotype
    Parental gametes (TR, Tr, tR, tr) shown
    Correct Crosses of parental gamete
    Phenotypic ratio 9:3:3:1

    (iii) Calculation of Tall and White flowers in F2
    (3/16) x (160/1) = 30

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