In which of the following reactions is sulphur dioxide acting as an oxidizing agent?
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Correct Answer: Option D
Explanation:
In reaction D, sulfur dioxide (SOâ‚‚) is acting as an oxidizing agent. Here's why:
Reaction D: SOâ‚‚ + 2Hâ‚‚S → 3S + 2Hâ‚‚O
In this reaction, sulfur dioxide (SOâ‚‚) is being reduced, while hydrogen sulfide (Hâ‚‚S) is oxidized. Specifically, SOâ‚‚ gains electrons (reduction) and is transformed into elemental sulfur (S), while Hâ‚‚S loses electrons (oxidation) and is converted into water (Hâ‚‚O).
Thus, SOâ‚‚ acts as an oxidizing agent because it accepts electrons from Hâ‚‚S, facilitating the oxidation of Hâ‚‚S.
In reaction D, sulfur dioxide (SOâ‚‚) is acting as an oxidizing agent. Here's why:
Reaction D: SOâ‚‚ + 2Hâ‚‚S → 3S + 2Hâ‚‚O
In this reaction, sulfur dioxide (SOâ‚‚) is being reduced, while hydrogen sulfide (Hâ‚‚S) is oxidized. Specifically, SOâ‚‚ gains electrons (reduction) and is transformed into elemental sulfur (S), while Hâ‚‚S loses electrons (oxidation) and is converted into water (Hâ‚‚O).
Thus, SOâ‚‚ acts as an oxidizing agent because it accepts electrons from Hâ‚‚S, facilitating the oxidation of Hâ‚‚S.