When excess ethanol is heated to 145 oC in the presence of concentrated sulphuric acid, the product is
Take Free Practice Test On 2026 JAMB UTME, Post UTME, WAEC SSCE, GCE, NECO SSCE
Correct Answer: Option A
Explanation:
The correct answer is A: diethyl ether.
When ethanol (Câ‚‚Hâ‚…OH) is heated with concentrated sulfuric acid (Hâ‚‚SOâ‚„) at around 145°C, it undergoes a dehydration reaction to form diethyl ether (Câ‚‚Hâ‚…OCâ‚‚Hâ‚…). This reaction is an example of etherification, where two ethanol molecules combine, eliminating water (Hâ‚‚O) in the presence of the concentrated sulfuric acid as a catalyst.
The reaction can be represented as:
\[
2C_2H_5OH \xrightarrow{H_2SO_4, 145^\circ C} C_2H_5OC_2H_5 + H_2O
\]
Thus, diethyl ether is the primary product of this reaction.
The correct answer is A: diethyl ether.
When ethanol (Câ‚‚Hâ‚…OH) is heated with concentrated sulfuric acid (Hâ‚‚SOâ‚„) at around 145°C, it undergoes a dehydration reaction to form diethyl ether (Câ‚‚Hâ‚…OCâ‚‚Hâ‚…). This reaction is an example of etherification, where two ethanol molecules combine, eliminating water (Hâ‚‚O) in the presence of the concentrated sulfuric acid as a catalyst.
The reaction can be represented as:
\[
2C_2H_5OH \xrightarrow{H_2SO_4, 145^\circ C} C_2H_5OC_2H_5 + H_2O
\]
Thus, diethyl ether is the primary product of this reaction.