N\(_2\)O\(_4\) ⇔ 2NO\(_2\) (Δ = -ve)
From the reaction above, which of these conditions would produce the highest equilibrium yield for N\(_2\)O\(_4\)?
From the reaction above, which of these conditions would produce the highest equilibrium yield for N\(_2\)O\(_4\)?
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Correct Answer: Option A
Explanation:
Low temperature and high pressure favor the highest yield for N\(_2\)O\(_4\)
Low temperature and high pressure favor the highest yield for N\(_2\)O\(_4\)