28.8 cm3 of nitrogen at 15°C is cooled to O°C at constant pressure, the new volume of nitrogen is?
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Correct Answer: Option C
Explanation:
(V1)/(T1) = (V2)/(T2) (288 cm3)/(288) = (V2)/(273)
V2 = (288 x 273)/(288) = 273 cm3
(V1)/(T1) = (V2)/(T2) (288 cm3)/(288) = (V2)/(273)
V2 = (288 x 273)/(288) = 273 cm3