Pure sulphuric acid is a liquid of 1:84 density. What volume of it would be required to prepare 250 cm3 of 2.0 M solution?
(H = 1, S = 32, O = 16)
(H = 1, S = 32, O = 16)
Take Free Practice Test On 2026 JAMB UTME, Post UTME, WAEC SSCE, GCE, NECO SSCE
Correct Answer: Option B
Explanation:
1000 cm3 of 1 m H2SO4 contains 98 gm of H2SO4
250 of 1 m H2SO4 (98)/(4) x (2)/(10) = 4.9 gm
But density = (mass)/(volume)
Volume = (Mass)/(Density) (4.90)/(1.84) = 2.66
1000 cm3 of 1 m H2SO4 contains 98 gm of H2SO4
250 of 1 m H2SO4 (98)/(4) x (2)/(10) = 4.9 gm
But density = (mass)/(volume)
Volume = (Mass)/(Density) (4.90)/(1.84) = 2.66