If one mole of aluminium contains 6 x 1023 atoms of aluminium, how many atoms are contained in 0.9g of aluminium?
(Al = 27)
(Al = 27)
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Correct Answer: Option C
Explanation:
1 Mole or 27 gms of Al contains 6 x 1021 atoms
0.9 gms of Al will contain (6 x 1023 x 0 g)/(27 1) = 0.2 x 1023 or 1022
1 Mole or 27 gms of Al contains 6 x 1021 atoms
0.9 gms of Al will contain (6 x 1023 x 0 g)/(27 1) = 0.2 x 1023 or 1022