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A current of 10.0A was passed for 1 hour through a solution of copper (ll) sulphate ...

A current of 10.0A was passed for 1 hour through a solution of copper (ll) sulphate between the copper electrodes. Which of the following observation would be correct?
(1 Faraday = 96,500 coulobms) (i) 0.186 mole of copper is dissolved from the anode. (ii) 0.372 mole of copper is deposited on the cathode. (iii) the original Cu2+ ion concentration of the solution remains unchanged. (iv) the original Cu2+ ion concentration of the solution decreases.
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  • A I and ii
  • B I and iii
  • C I and iv
  • D Ii and iii
  • E Ii and iv
Correct Answer: Option B
Explanation:

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