Given that the molecular mass of iron is 56 and that of oxygen is 16, how many moles of iron(iii)oxide will be contained in 1kg of the compound?
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Correct Answer: Option C
Explanation:
Fe2O3 = 56 x 2 + 48 = 160 = 1 moles
1000gm will contain \(\frac{1000}{160}\) = 6.25 moles
Fe2O3 = 56 x 2 + 48 = 160 = 1 moles
1000gm will contain \(\frac{1000}{160}\) = 6.25 moles