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Cr2O7 + 6Fe2+ + 14H+ → 2Cr3+ +6Fe3+ + 7H2O. In the above , the ...
Classroom
Chemistry Classroom
Jamb
Jamb 1990
Oxidation And Reduction
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Cr
2
O
7
+ 6Fe
2+
+ 14H
+
→ 2Cr
3+
+6Fe
3+
+ 7H
2
O. In the above , the oxidation number of chromium changed from?
SchoolNGR Classroom
Take Free Practice Test On 2026 JAMB UTME, Post UTME, WAEC SSCE, GCE, NECO SSCE
A
+7 to +3
B
+6 to +3
C
+5 to +3
D
-2 to +3
Show Answer
Show Explanation
Correct Answer:
Option A
Explanation:
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