How many grams of bromine will be required to completely react with 10 g of propyne?
(C = 12, H = 1, Br = 80)
(C = 12, H = 1, Br = 80)
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Correct Answer: Option D
Explanation:
C3H4 + 2Br2 - C3Br4 + 2H2
(36 + 4) (4 X 80)
40 g of C3H4 reacts with 320 g of Br
10 " " will react with
(10)/(40) x (320) /(1) = 80g
C3H4 + 2Br2 - C3Br4 + 2H2
(36 + 4) (4 X 80)
40 g of C3H4 reacts with 320 g of Br
10 " " will react with
(10)/(40) x (320) /(1) = 80g