If 100 cm3 of oxygen pass through a porous plug in 50 seconds, the time taken for the same volume of hydrogen to pass through the same porous plug is?
(O = 16, H = 1)
(O = 16, H = 1)
Take Free Practice Test On 2026 JAMB UTME, Post UTME, WAEC SSCE, GCE, NECO SSCE
Correct Answer: Option B
Explanation:
100 cm3 of O2 diffuse 50 sec
∴ 100 cm3 of H2 → (100) / (100) x (50) /(1)
t1 50 sec
molecular mass H+ → 2 x 1 = 2
molecular mass of O2 16 x 2 = 32
T2 = t1 √M2/M1 = t2 = 50 √2/32
50√0.625 = 50 x 0.25 = 12.5 secs
100 cm3 of O2 diffuse 50 sec
∴ 100 cm3 of H2 → (100) / (100) x (50) /(1)
t1 50 sec
molecular mass H+ → 2 x 1 = 2
molecular mass of O2 16 x 2 = 32
T2 = t1 √M2/M1 = t2 = 50 √2/32
50√0.625 = 50 x 0.25 = 12.5 secs