How many grams of H2SO4 are necessary for the preparation of 0.175 dm3 of M 6.00 M H2SO4?
(S = 32.06, O = 16.00 H = 1.00)
(S = 32.06, O = 16.00 H = 1.00)
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Correct Answer: Option B
Explanation:
1 mole of H2SO4 ≈ 98 gms
0.175 dm3 of 6.0 m H2SO4
1000 cm3 ≈ dm3
(0.175) / (1000) of 6.0 m H2SO4
0.000175 x 6 x 98 ≈ 0.1029 gms
1 dm3 - 1000 cm3
∴ 0.1029 x 1000 = 103 gms
1 mole of H2SO4 ≈ 98 gms
0.175 dm3 of 6.0 m H2SO4
1000 cm3 ≈ dm3
(0.175) / (1000) of 6.0 m H2SO4
0.000175 x 6 x 98 ≈ 0.1029 gms
1 dm3 - 1000 cm3
∴ 0.1029 x 1000 = 103 gms