How many moles of oxygen molecules would be produced from the decomposition of 2.50 moles of potassium trioxochlorate (V)?
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Correct Answer: Option C
Explanation:
2KClO3(s) → 2KCl(s) + 3O2(g)
From the above balanced equation, 2 moles of reactant decomposed to give 3 moles of O2 i.e.
i mole of reactant will produce (3)/(2) moles O2.
∴ 2.5 moles KClO3 will give
= 3.75 moles
2KClO3(s) → 2KCl(s) + 3O2(g)
From the above balanced equation, 2 moles of reactant decomposed to give 3 moles of O2 i.e.
i mole of reactant will produce (3)/(2) moles O2.
∴ 2.5 moles KClO3 will give
= 3.75 moles