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RS(aq) + HF(aq) → RF(s) + HS(aq) ΔH = -65.7 kj ...

RS(aq) + HF(aq) → RF(s) + HS(aq)
ΔH = -65.7 kj mol(-1).
From the equation above, it can be deduced that
Take Free Practice Test On 2026 JAMB UTME, Post UTME, WAEC SSCE, GCE, NECO SSCE
  • A The heat content of the reactants is lower than that of the products
  • B The heat content of the reactants is higher than that of the products
  • C The reaction is slow
  • D A large amount of heat is absorbed
Correct Answer: Option B
Explanation:

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