50 cm3 of carbon (II) oxide was exploded with 150 cm3 of air containing 20% oxygen by volume. Which of the reactants was in excess?
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Correct Answer: Option C
Explanation:
2CO + O2 → 2CO2
50cm3 → 25cm3
20% * 150 = 30cm3
30 cm3 is the volume of oxygen available for the reactions. But only 25 cm3 is required; therefore O2 is in excess
2CO + O2 → 2CO2
50cm3 → 25cm3
20% * 150 = 30cm3
30 cm3 is the volume of oxygen available for the reactions. But only 25 cm3 is required; therefore O2 is in excess