The partial pressure of oxygen in a sample of air is 452 mm Hg and the total pressure is 780 mm Hg. What is the mole fraction of oxygen?
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Correct Answer: Option B
Explanation:
Mole fraction = \(\frac{\text{Partial pressure of component}}{\text{Total pressure of compound}}\)
= \(\frac{452}{780}\)
= 0.579
Mole fraction = \(\frac{\text{Partial pressure of component}}{\text{Total pressure of compound}}\)
= \(\frac{452}{780}\)
= 0.579