The pOH of a solution of 0.25 mol dm-3 of hydrochloric acid is
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Correct Answer: Option B
Explanation:
pOH = -log [2.5 * 10-1]
= -log[-0.3979 + 1]
= 13.40
pOH = -log [2.5 * 10-1]
= -log[-0.3979 + 1]
= 13.40