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(1/2)Zn2+(aq) + e- → (1/2) Zn(s) In the reaction above, calculate ...

(1/2)Zn2+(aq) + e- → (1/2) Zn(s)
In the reaction above, calculate the quantity of electricity required to discharge zinc.
[F = 96 500 C mol-1]
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  • A 0.965 * 104C
  • B 4.820 * 104C
  • C 9.650 * 104C
  • D 48.200 * 104C
Correct Answer: Option C
Explanation:
1 mol → 96500 * 2
0.5 mol → X
X = 0.5 * 96500 * 2
= 9.650 * 104C

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