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2SO2(g) + O2(g) ↔ 2SO3(g) ΔH = -189 kJ mol-1 The ...

2SO2(g) + O2(g) ↔ 2SO3(g)
ΔH = -189 kJ mol-1
The equilibrium constant for the reaction above is increased by
Take Free Practice Test On 2026 JAMB UTME, Post UTME, WAEC SSCE, GCE, NECO SSCE
  • A Increasing the temperature of the system
  • B Increase the pressure of the system
  • C The addition of a catalyst to the system
  • D Increasing the surface area of the vessel
Correct Answer: Option B
Explanation:

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