The mass of silver deposited when a current of 10a is passed through a solution of silver salt for 4830s is
[Ag = 108, F = 96500 c mol-1]
[Ag = 108, F = 96500 c mol-1]
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Correct Answer: Option B
Explanation:
Ag + ie → Ag+
If w 96500 C deposit 108g of silver
∴ 10 * 4830 will deposit (10 * 4830 * 108)/96500
= 5216400/96500 = 54.06g
Ag + ie → Ag+
If w 96500 C deposit 108g of silver
∴ 10 * 4830 will deposit (10 * 4830 * 108)/96500
= 5216400/96500 = 54.06g