The volume of 2.5 moles of oxygen at s.t.p is
[Molar volume of a gas at s.t.p = 22.4 dm3]
[Molar volume of a gas at s.t.p = 22.4 dm3]
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Correct Answer: Option D
Explanation:
1 mole of gas at s.t.p = 22.4
2.5 moles → 2.5 * 22.4 = 56.00 dm3
1 mole of gas at s.t.p = 22.4
2.5 moles → 2.5 * 22.4 = 56.00 dm3