How long would it take to deposit 0.08g of copper from CuCl2 solution by passing a current of 0.5A?
[Cu = 64, F = 96500 C mol-1]
[Cu = 64, F = 96500 C mol-1]
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Correct Answer: Option B
Explanation:
Cu2+ + 2e → Cu(s)
2 * 96500C deposit 64g of Cu
∴ x quantity of electricity wil deposit 0.08x = (2 * 96500 * 0.08)/64 =241.25 coulomb.
Q = It
241.25 = 0.5t
t = 241.25/60 = 8 mins
Cu2+ + 2e → Cu(s)
2 * 96500C deposit 64g of Cu
∴ x quantity of electricity wil deposit 0.08x = (2 * 96500 * 0.08)/64 =241.25 coulomb.
Q = It
241.25 = 0.5t
t = 241.25/60 = 8 mins