What is the volume of oxygen required to burn complete 45 cm3 of methane at s.t.p?
Take Free Practice Test On 2026 JAMB UTME, Post UTME, WAEC SSCE, GCE, NECO SSCE
Correct Answer: Option D
Explanation:
CH4(g) + 2O2(g) → 2H2O(g) + CO(g)
1 volume of methane will react with 90 cm3 of oxygen at s.t.p
CH4(g) + 2O2(g) → 2H2O(g) + CO(g)
1 volume of methane will react with 90 cm3 of oxygen at s.t.p