What is the pH of 0.001 mol dm-3 solution of sodium hydroxide
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Correct Answer: Option D
Explanation:
[H+] [OH-] = 10-14
[H+] = 10-14/[OH-] = 10-14/(1 * 10-3) = 10-11
pH = -Log10[H+]
= - Log10[10-11] = - 1 * -11 Log10[10-11] = 1 = -1 * -11 * 1 = 11
[H+] [OH-] = 10-14
[H+] = 10-14/[OH-] = 10-14/(1 * 10-3) = 10-11
pH = -Log10[H+]
= - Log10[10-11] = - 1 * -11 Log10[10-11] = 1 = -1 * -11 * 1 = 11