The rate of diffusion of a gas Y is twice that of Z If the relative molecular mass of Y is 64 and the two gases diffuse under the same conditions, find the relative molecular mass of Z
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Correct Answer: Option D
Explanation:
\(\sqrt{y}\) = 2x
\(\sqrt{Z}\) = x
\(\frac{rz}{ry}\) = \(\sqrt{\frac{my}{mz}}\)
\(\frac{2x}{x}\) = \(\sqrt{\frac{64}{mz}}\)
\(\frac{4}{1}\) = \(\frac{64}{mz}\)
mz = \(\frac{64}{4}\)
mz = 16
\(\sqrt{y}\) = 2x
\(\sqrt{Z}\) = x
\(\frac{rz}{ry}\) = \(\sqrt{\frac{my}{mz}}\)
\(\frac{2x}{x}\) = \(\sqrt{\frac{64}{mz}}\)
\(\frac{4}{1}\) = \(\frac{64}{mz}\)
mz = \(\frac{64}{4}\)
mz = 16