10.0 dm3 of water was added to 2.0 mol dm-3 of 2.5dm3 solution of HCl. What is the concentration of the final solution in mol dm-3?
Take Free Practice Test On 2026 JAMB UTME, Post UTME, WAEC SSCE, GCE, NECO SSCE
Correct Answer: Option A
Explanation:
C1V1 = C2V2
C2 = \(\frac{C_1V_1}{V_2}\)
= \(\frac{2.0 \times 2.5}{12.5}\)
= 0.4mol/dm-3
C1V1 = C2V2
C2 = \(\frac{C_1V_1}{V_2}\)
= \(\frac{2.0 \times 2.5}{12.5}\)
= 0.4mol/dm-3