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Cr 2O\(\frac{2 -}{7}\) (aq) + H 2O(1)⇌ 2CrO \(\frac{2 -}{4}\) (aq) ...

Cr 2O\(\frac{2 -}{7}\) (aq) + H 2O(1)⇌ 2CrO \(\frac{2 -}{4}\) (aq) + 2H + (aq)
What happens to the reaction above when the hydrogen ion concentration is increased?
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  • A More of the products will be formed
  • B The reaction will not proceed
  • C The equilibrium position will shift to the right
  • D The equilibrium position will shift to the left.
Correct Answer: Option D
Explanation:

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