A fixed mass of gas a volume of 92cm3 at 3°C. When will be its volume at 18C if the pressure remains constant?
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Correct Answer: Option D
Explanation:
\(\frac{V_{1}}{T_{1}}\) = \(\frac{V_{2}}{T_{2}}\)
\(T_{1}\) = 3 + 273 = 276K
\(T_{2}\) = 18 + 273 = 291K
\(V_{1}\) = \(92cm^{3}\)
\(V_{2}\) = ?
\(V_{2}\) = \(\frac{V_{1}T_{2}}{T_{1}}\)
=\(\frac{92 \times 291}{276}\)Â
= \(97.0cm^{3}\)
\(\frac{V_{1}}{T_{1}}\) = \(\frac{V_{2}}{T_{2}}\)
\(T_{1}\) = 3 + 273 = 276K
\(T_{2}\) = 18 + 273 = 291K
\(V_{1}\) = \(92cm^{3}\)
\(V_{2}\) = ?
\(V_{2}\) = \(\frac{V_{1}T_{2}}{T_{1}}\)
=\(\frac{92 \times 291}{276}\)Â
= \(97.0cm^{3}\)