What is the volume of energy required to burn 45cm\(^3\) of mixture at S.T.P
Take Free Practice Test On 2026 JAMB UTME, Post UTME, WAEC SSCE, GCE, NECO SSCE
Correct Answer: Option D
Explanation:
CH4(g) + 2O2(g) → 2H2O(g)
1 volume of methane will react with 90cm\(^3\) of oxygen at S.T.P
CH4(g) + 2O2(g) → 2H2O(g)
1 volume of methane will react with 90cm\(^3\) of oxygen at S.T.P