The densities of two gases, X and Y are 0.5gdm-3 and 2.0gdm-3 respectively. What is the rate of diffusion of X relative to Y?
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Correct Answer: Option C
Explanation:
The rate of dimension of a gas inversely proportional to the square root of its molecular mass or its density, which is Graham's Law of diffusion of gas.
R ∠\(\frac{1}{\sqrt{Mm}}\) or R ∠\(\frac{1}{\sqrt{D}}\)
Dx = 0.5gdm-3, Dy = 2gdm-3
R= \(\frac{K}{\sqrt{D}}\)
R\(\sqrt{D}\) = k
R1\(\sqrt{D_1}\) = R1\(\sqrt{D_2}\)
Rx\(\sqrt{D_x}\) = Ry\(\sqrt{D_y}\)
\(\frac{R_x}{R_y}\) = \(\frac{\sqrt{D_y}}{\sqrt{D_x}}\)
= \(\frac{\sqrt{2}}{\sqrt{0.5}}\)
= 2.0
The rate of dimension of a gas inversely proportional to the square root of its molecular mass or its density, which is Graham's Law of diffusion of gas.
R ∠\(\frac{1}{\sqrt{Mm}}\) or R ∠\(\frac{1}{\sqrt{D}}\)
Dx = 0.5gdm-3, Dy = 2gdm-3
R= \(\frac{K}{\sqrt{D}}\)
R\(\sqrt{D}\) = k
R1\(\sqrt{D_1}\) = R1\(\sqrt{D_2}\)
Rx\(\sqrt{D_x}\) = Ry\(\sqrt{D_y}\)
\(\frac{R_x}{R_y}\) = \(\frac{\sqrt{D_y}}{\sqrt{D_x}}\)
= \(\frac{\sqrt{2}}{\sqrt{0.5}}\)
= 2.0