To what volume must 300cm\(^3\) of 0.60M sodium hydroxide solution be diluted to give a 0.40M solution?
Take Free Practice Test On 2026 JAMB UTME, Post UTME, WAEC SSCE, GCE, NECO SSCE
Correct Answer: Option A
Explanation:
From the dilution law
 C\(_1\)V\(_1\) = C\(_2\)V\(_2\)
 C\(_1\) = Initial Concentration of NaOH = 0.6M
 V\(_1\) = Initial Volume of NaOH = 300cm3
 C\(_2\) = Final Concentration of NaOH = 0.4M
 V\(_2\) = Final Volume of NaOH = ?
 V\(_2\) = \(\frac{C_1V_1}{C_2}\)
 V\(_2\) = \(\frac{0.6 \times 300}{0.4}\)
 V\(_2\) = 450 cm\(^3\)
Correct Computation as it follows the equation specified
From the dilution law
 C\(_1\)V\(_1\) = C\(_2\)V\(_2\)
 C\(_1\) = Initial Concentration of NaOH = 0.6M
 V\(_1\) = Initial Volume of NaOH = 300cm3
 C\(_2\) = Final Concentration of NaOH = 0.4M
 V\(_2\) = Final Volume of NaOH = ?
 V\(_2\) = \(\frac{C_1V_1}{C_2}\)
 V\(_2\) = \(\frac{0.6 \times 300}{0.4}\)
 V\(_2\) = 450 cm\(^3\)
Correct Computation as it follows the equation specified