Calculate the pH of 0.05 moldm\(^{-3}\) H\(_2\)SO\(_4\)
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Correct Answer: Option C
Explanation:
Recall from pH formula pH = -Log [H+]
 H2SO4 → 2H+ + SO42-
 2H+ → 2 X0.05 = 0.1
 pH= -Log [0.1] = 1
Recall from pH formula pH = -Log [H+]
 H2SO4 → 2H+ + SO42-
 2H+ → 2 X0.05 = 0.1
 pH= -Log [0.1] = 1