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Consider the reaction: A + 2B\(_{(g)} \rightleftharpoons\) 2C + D\(_{(g)}\) ...

Consider the reaction: A + 2B\(_{(g)} \rightleftharpoons \) 2C + D\(_{(g)}\) (\(\Delta\)H = +ve)
What will be the effect of decrease in temperature on the reaction?
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  • A Rate of backward reaction will increase
  • B The equilibrium constant will shift
  • C Rates of forward and backward reactions are not affected
  • D Rate of forward reaction will increase
Correct Answer: Option A
Explanation:
The given reaction is endothermic, hence, a decrease in temperature will favor the exothermic side which is the backward reaction.

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