Hydrogen diffused through a porous plug
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Correct Answer: Option C
Explanation:
Using Graham's Law of Diffusion,
\(\frac{R_1}{R_2} = \sqrt{\frac{m_2}{m_1}}\)
\(\frac{R_H}{R_O} = \sqrt{\frac{m_O}{m_H}}\)
\(\frac{R_H}{R_O} = \sqrt{\frac{32}{2}}\)
\(\frac{R_H}{R_O} = \sqrt{16} = 4\)
\(\therefore R_H = 4 \times R_O\)
Therefore, hydrogen diffuses 4 times faster than oxygen.
Using Graham's Law of Diffusion,
\(\frac{R_1}{R_2} = \sqrt{\frac{m_2}{m_1}}\)
\(\frac{R_H}{R_O} = \sqrt{\frac{m_O}{m_H}}\)
\(\frac{R_H}{R_O} = \sqrt{\frac{32}{2}}\)
\(\frac{R_H}{R_O} = \sqrt{16} = 4\)
\(\therefore R_H = 4 \times R_O\)
Therefore, hydrogen diffuses 4 times faster than oxygen.