What volume of hydrogen is produced at s.t.p. When 2.60 g of zinc reacts with excess HCI according to the following equation? Zn(s) + 2HCI(aq) → ZnCI 2(aq) + H2(g) [Zn = 65; 1 mole of a gas occupies 22.4dm3 at s.t.p]
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Correct Answer: Option B
Explanation:
Zn + 2HCI → ZnCI2 + H2; 65g of Zn produces 22.4 dm3 of H2; .: 2.6g of Zn will produce = 2.6/65 x 22.4 = 0.896 dm3
Zn + 2HCI → ZnCI2 + H2; 65g of Zn produces 22.4 dm3 of H2; .: 2.6g of Zn will produce = 2.6/65 x 22.4 = 0.896 dm3