A feasible cell was constructed by joining the two half cells below. Cu2+(aq) + 2e- → Cu(s) Eo = - 0.76 V. What is the standard e.m.f. of the cell?
Take Free Practice Test On 2026 JAMB UTME, Post UTME, WAEC SSCE, GCE, NECO SSCE
Correct Answer: Option D
Explanation:
e.m.f. = + 0.34 -(-0.76) = 0.34 + 0.76 = +1.1V
e.m.f. = + 0.34 -(-0.76) = 0.34 + 0.76 = +1.1V