An atom 23892X decays by alpha particle emission to give an atom Y. The atomic number and mass number of Y are - SchoolNGR

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An atom 23892X decays by alpha particle emission to give an atom Y. The atomic number ...

An atom ²³⁸₉₂X decays by alpha particle emission to give an atom Y. The atomic number and mass number of Y are

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Take Free Practice Test On 2026 JAMB UTME, Post UTME, WAEC SSCE, GCE, NECO SSCE

A 90 and 234 respectively
B 91 and 238 respectively
C 92 and 236 respectively
D 93 and 238 respectively

Correct Answer: Option A

Explanation:
238₉₂ X 234 ₉₀Y + ^{4 ₂ He Atomic number is 90 while mass number is 234}

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