If 20 cm3 of distilled water is added to 80cm 3 of 0. 50 mol dm-3 hydrochloric acid, the new concentration of the acid will be
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Correct Answer: Option D
Explanation:
C1 x 100 = 0.5 x 80
C1 = \(\frac{0.5 x 80}{100}/) = \(\frac{4}{10}/) = 0 . 40mol/dm-3
C1 x 100 = 0.5 x 80
C1 = \(\frac{0.5 x 80}{100}/) = \(\frac{4}{10}/) = 0 . 40mol/dm-3