Atom \(^{234} _{88} Q\) decay by alpha emission to give an atom R. The atomic number and mass number of atom R are respectively
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Correct Answer: Option A
Explanation:
\(^{234} _{88} Q \to R + ^4 _2 He\)
\(\therefore R = ^{234 - 4} _{88 - 2} R\)
= \(^{230} _{86} R\)
\(^{234} _{88} Q \to R + ^4 _2 He\)
\(\therefore R = ^{234 - 4} _{88 - 2} R\)
= \(^{230} _{86} R\)