How many moles of oxygen would contain 1.204 x 1024 molecules?
[Avogadro's constant (NA) = 6.02 x 1023]
[Avogadro's constant (NA) = 6.02 x 1023]
Take Free Practice Test On 2026 JAMB UTME, Post UTME, WAEC SSCE, GCE, NECO SSCE
Correct Answer: Option B
Explanation:
6.02 x 1023 molecules is 1mole
1.204 x 1024 molecules will be......
\(\frac{1.204 \times 10^24 \times 1}{6.02 \times 10^23}\)
\(\frac{1.204 \times 10}{6.02}\) = \(\frac{12.04}{6.02}\) = 2moles
6.02 x 1023 molecules is 1mole
1.204 x 1024 molecules will be......
\(\frac{1.204 \times 10^24 \times 1}{6.02 \times 10^23}\)
\(\frac{1.204 \times 10}{6.02}\) = \(\frac{12.04}{6.02}\) = 2moles