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(a) (i) Draw the structures of the isomers of the alkene with molecular formurat ...

(a) (i) Draw the structures of the isomers of the alkene with molecular formurat C\(_4\)H\(_8\)
(ii) State the class of alkanols to which each of the following compounds belongs:
I. CH\(_3\)C(CH\(_3\))\(_2\)OH;
II. CH\(_3\)CH(CH\(_3\))CH\(_2\)OH;
III. CH\(_3\)CH\(_2\)CH(CH\(_3\))OH.

(b) (i) Write the formulae of the products formed in the following reactions:
I. CH\(_3\)CH\(_2\)COOH \(\frac{K_{(s)}}{}\)
II. CH\(_3\)CH\(_2\)COOH. \(\frac{C_4H_6OH, heat}{Conc.H_2SO_4}\)
III. CH\(_3\)CH\(_2\)CH\(_2\)CH\(_2\)OH \(\frac{H^+/KMnO_4}{(excess)}\)
(ii) Name the major product(s) of each of the reactions in (b)(i).

(c) A gaseous hydrocarbon R of mass 7.0 g occupies a volume of 2.24 dm\(^3\) at s. t.p. If the percentage composition by mass of hydrogen is 14.3, determine its:
(i) empirical formula;
(ii) molecular formula. [ H = 1.00, C = 12.0, Molar volume of gas at s.t.p, = 22.4 dm\(^3\) ]

(d) Define structural isomerism.
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    Correct Answer: Option
    Explanation:



    (a)(i) Structural Isomers of C\(_4\)H\(_4\)

    (ii) (I)Tertiary(3°)alkanol.

    (II) Primary (1°)alkanol.

    (III) Secondary (2°) alkanol



    (b)(i)

    (I) CH\(_3\)CH\(_2\)COOK, H\(_2\)

    (II) CH\(_3\)CH\(_2\)COOC\(_4\)H\(_9\) H\(_2\)O

    (III) CH\(_3\)CH\(_2\)CH\(_2\)COOH

    (ii) Major products in (b)(i) (1) — Potassuim propanoate (II) — Butyl propanoate (III) — Butanoic acid



    (C)(i) % carbon by mass = 100 – 14.3 (l) = 85.7%

    Ratio of atoms = \(\frac{C}{\frac{85.7}{12.0}}\) = 7.1415; \(\frac{H}{\frac{14.3}{1.0}}\) = 14.3

    Divide by smaller number = \(\frac{7.1415}{7.1415}\) = 1; \(\frac{14.3015}{7.1415}\) = 2

    Empirical Formular = CH\(_2\)



    (i) 2.24dm\(^3\) = 7.0g of R

    22.4dm\(^3\) = \(\frac{7.0}{2.24}\) x 22.4 = 70gmol\(^1\)

    OR

    Molar volume of gas = 22.4 dm\(^3\) at s.t.p 22.4

    22.4 dm\(^3\) gas = 1 mole

    22.4 dm\(^3\) = \(\frac{2.24}{22.4} \times 1\) = 0.1 mol

    But numbers of moles = 0.1

    Mr = \(\frac{7}{0.1}\) = 70gmol\(^1\)

    Molecular formular = C\(_5\)H\(_{10}\)

    (CH_2)n = 70

    14n = 70

    n = \(\frac{70}{4}\) = 5



    (d) The occurence of / existence of / condition whereby compounds with the same molecular formula have different structural formulae.

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