If 0.2g of a salt is required to saturate 200\(cm^{3}\) of water at room temperature, what is the solubility of the salt?
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Correct Answer: Option B
Explanation:
Solubility in \(gdm^{-3}\) = \(\frac{mass of salt in gram}{volume of liquid in dm^{3}}\)
200\(cm^{3}\) = \(\frac{200}{1000} dm^{3} = 0.2dm^{3}\)
Solubility = \(\frac{0.2g}{0.2dm^{3}}\)
= 1.0\(gdm^{-3}\)
Solubility in \(gdm^{-3}\) = \(\frac{mass of salt in gram}{volume of liquid in dm^{3}}\)
200\(cm^{3}\) = \(\frac{200}{1000} dm^{3} = 0.2dm^{3}\)
Solubility = \(\frac{0.2g}{0.2dm^{3}}\)
= 1.0\(gdm^{-3}\)