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How many atoms are contained in 0.2moles of nitrogen? \([N_{A} = 6.02 \times 10^{23}]\)

How many atoms are contained in 0.2moles of nitrogen? \([N_{A} = 6.02 \times 10^{23}]\)
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  • A \(1.20 \times 10^{23}\)
  • B \(2.41 \times 10^{23}\)
  • C \(3.62 \times 10^{23}\)
  • D \(4.82 \times 10^{23}\)
Correct Answer: Option A
Explanation:
\(1 mole = 6.02 \times 10^{23} atoms\)
\(0.2 moles = 6.02 \times 10^{23} \times 0.2\) atoms
= \(1.204 \times 10^{23}\)
\(\approxeq 1.2 \times 10^{23}\)

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