Analysis of a hydrocarbon shows that it contains 0.93g of Carbon per gram of the compound. The mole ratio of carbon to hydrogen in the compound is [H = 1.0, C=12.0]
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Correct Answer: Option A
Explanation:
1g of Hydrocarbon = 0.93g of Carbon, therefore, Hydrogen = (1 - 0.93)g = 0.07g
C : H
0.93 : 0.07
\(\frac{0.93}{12}\) : \(\frac{0.07}{1}\)
0.078 : 0.07
\(\frac{0.078}{0.07} : \frac{0.07}{0.07}\)
\(\approxeq 1:1\)
1g of Hydrocarbon = 0.93g of Carbon, therefore, Hydrogen = (1 - 0.93)g = 0.07g
C : H
0.93 : 0.07
\(\frac{0.93}{12}\) : \(\frac{0.07}{1}\)
0.078 : 0.07
\(\frac{0.078}{0.07} : \frac{0.07}{0.07}\)
\(\approxeq 1:1\)