Mg(s) + 2HCl(aq) → MgCl2(aq) + H2(g)
From the equation above, the mass of magnesium required to react with 250cm3 of 0.5M HCl is [Mg = 24]
From the equation above, the mass of magnesium required to react with 250cm3 of 0.5M HCl is [Mg = 24]
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Correct Answer: Option B
Explanation:
Molar conc. =no.of in dm3
Vol=250cm3 = 0.25dm3
Molar conc = 0.5M
No of moles = molar conc *Vol in dm3
=0.5*0.25
=0.125mole of HCl
2moles of HCl → of Mg
0.125 mole →(0.125*1)/2
=0.0625mole of Mg
Reacting mass=no of moles* molar mass
Mg=24
Mass=0.0625*24
=1.5g
Molar conc. =no.of in dm3
Vol=250cm3 = 0.25dm3
Molar conc = 0.5M
No of moles = molar conc *Vol in dm3
=0.5*0.25
=0.125mole of HCl
2moles of HCl → of Mg
0.125 mole →(0.125*1)/2
=0.0625mole of Mg
Reacting mass=no of moles* molar mass
Mg=24
Mass=0.0625*24
=1.5g