The volume occupied by 1.58g of a gas at S.T.P is 500cm\(^3\). What is the relative molecular mass of the gas? [ G.M.V at S.T.P = 22.4dm\(^{3}\) ]
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Correct Answer: Option D
Explanation:
500cm\(^3\) of the gas weighed 1.58
: 22400cm\(^3\) of the gas weight
[22400 X 1.58g] ÷ [ 500 ]
= 71
500cm\(^3\) of the gas weighed 1.58
: 22400cm\(^3\) of the gas weight
[22400 X 1.58g] ÷ [ 500 ]
= 71