An organic compound contains 72% carbon, 12% hydrogen and 16% oxygen by mass. What is the empirical formula of the compound?
[ H = 1.0. C = 12.0, O = 16.0 ]
[ H = 1.0. C = 12.0, O = 16.0 ]
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Correct Answer: Option B
Explanation:
C = 72 / 12 H = 12 / 1 O = 16 / 16
C = 6 H = 12 O = 1
: EMPIRICAL FORMULA
C\(_6\)H\(_12\)O
C = 72 / 12 H = 12 / 1 O = 16 / 16
C = 6 H = 12 O = 1
: EMPIRICAL FORMULA
C\(_6\)H\(_12\)O