. If 20 cm\(^3\) of sodium hydroxide was neutralized by 20 cm\(^3\) of 0.01 mol dm3 tetraoxosulphate(VI) acid, what is the concentration of the solution?
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Correct Answer: Option B
Explanation:
\(frac{CaVa}{CbVb}\) = \(frac{Na}{Nb}\)
( 0.01 X 20 ) / (Cb X 20) = 1 / 2
cross multiply → Cb = (0.01 X 20 X 2) / ( 20 X 1)
Cb = 0.02 mol/dm\(^3\)
\(frac{CaVa}{CbVb}\) = \(frac{Na}{Nb}\)
( 0.01 X 20 ) / (Cb X 20) = 1 / 2
cross multiply → Cb = (0.01 X 20 X 2) / ( 20 X 1)
Cb = 0.02 mol/dm\(^3\)