What mass of copper in gram would be deposited by a current of 1.00ampere passing for 965 seconds through copper(II) tertraoxosulphate (VI) solution? [Cu 63.5; If = 96500c]
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Correct Answer: Option A
Explanation:
Recall that two faradays ( 2 X 96500 ) will be required to discharge 1 mole of a divalent ion like Cu.
2 X 96500 will deposit 63.5g of Cu
And 965C wiil deposit x-grams
CROSS MULTIPLY
(965 X 63.5) ÷ ( 2 X 96500)
= 0.3175
Recall that two faradays ( 2 X 96500 ) will be required to discharge 1 mole of a divalent ion like Cu.
2 X 96500 will deposit 63.5g of Cu
And 965C wiil deposit x-grams
CROSS MULTIPLY
(965 X 63.5) ÷ ( 2 X 96500)
= 0.3175